Question

solve:
(11/3x)-(1/3)=(-4/x^2)

Answer 1

multiply evrything by 3x^2

11x - x^2 = -12

that should be easier now

Answer 2

uhm I have no idea what that just did?

Answer 3

lgbasallote found the LCD of 3x,x,x^2 and multiplied that with everything to get rid of the denominator :o

Answer 4

then it would be a simple quadratic which you can solve easily :D

Answer 5

lol sorry for jumping that...i assumed you knew LCMs :S

Answer 6

\[\frac{11}{3x}-\frac{1}{3}=\frac{-4}{x^2}\]

Answer 7

so right now the answer is 11x-x^2=-12?
and it's okay but no i don't really know what i'm doing.

Answer 8

thats fine with me, less work.

Answer 9

Let's add the two fractions on the left and then you can cross multiply like before.

Answer 10

\[\frac{11}{3x}-\frac{1}{3}\times\frac{x}{x}=\frac{-4}{x^2}\]

Answer 11

\[\frac{11-x}{3x}=\frac{-4}{x^2}\]

Answer 12

Cross multiply

Answer 13

so it would be\[11x ^{2}-x ^{3}\div -12x\]?

Answer 14

\[11x^2-x^3=-12x\]

Answer 15

So let's get it equal to 0.

Answer 16

oh

Answer 17

\[x^3-11x^2-12x=0\]

Answer 18

Now we can factor it.
Factor out an x:
\[x(x^2-11x-12)=0\]
\[x(x-12)(x+1)=0\]
x=0, x=12, x = -1

Answer 19

But of course x cannot be 0 because then the denominator would be 0 so we will discard that answer and keep 12 and -1 as answers.

Answer 20

Thanks. (: