Question

Graph : f(x) = (x-6)^2 + 5
Find the vertex and intercepts and axis of symmetry.

Answer 1

For a quadratic function f(x) = (x-h)^2 + k
vertex is at (h,k) and axis of symmetry is x=h
Now, h=6 and k=5. Can you get the answer for vertex and axis of symmetry?

For x-int. Put f(x) =0 and solve it
For y-int. Put x=0 and find the value of y.
Hope it helps :)

Answer 2

I'm still confused.

Answer 3

At which part??

Answer 4

Plugging in for the x and y intercept. Do you mind starting me off?

Answer 5

To find x-intercept(s), put y=0, that is f(x)=0
f(x) = (x-6)^2 + 5 =0
(x-6)^2 = -5
Solve x (there should be no x-intercepts in this case, as square root of -5 is not real.)

To find y-intercept, put x=0
f(0) = (0-6)^2 + 5 = (-6)^2 + 5 =?

Answer 6

So what would be the x-intercept?

Answer 7

No x-intercepts

Answer 8

Sorry I'm not the best at graphs.

Answer 9

See this:
http://www.wolframalpha.com/input/?i=y%3D%28x-6%29%5E2+%2B+5+
=> no x-intercepts

Answer 10

Okay for the y-intercept?

Answer 11

To find y-intercept, put x=0
f(0) = (0-6)^2 + 5 = (-6)^2 + 5 = ...?

Answer 12

I don't think I solved it correctly :/

Answer 13

Is it 41?

Answer 14

?

Answer 15

Yes, it is!

Answer 16

So what would the line of symmetry be?

Answer 17

?

Answer 18

axis of symmetry is x=h
and h=6
So.. axis of symmetry is x= .. ?