Question

Plz explain how to solve this problem...

Answer 1

first get common denominators... do you the least common denominator?

Answer 2

\[\large \frac {3}{x-1} + \frac {2}{x} = 4\]

Answer 3

\[\frac{3*x}{(x-1)*x} +\frac{2*(x-1)}{x*(x-1)} =4 => \frac{3x+2(x-1)}{x(x-1)} =4\]
can you do it now?

Answer 4

Yeah, thanks

Answer 5

another technique
\[\begin{array}{l} \frac{2}{x}+\frac{3}{x-1}=4 \\ \text{multiply both sides by }x-1 \\ \frac{2 (x-1)}{x}+3=4 (x-1) \\ \text{Expand out terms on both sides:} \\ 5-\frac{2}{x}=4 x-4 \\ \text{write the left hand side as a single fraction} \\ \frac{5 x-2}{x}=4 x-4 \\ \text{Multiply both sides by }x: \\ 5 x-2=4 x^2-4 x \\ \text{Subtract }\left(4 x^2-4 x\right)\text{ from both sides:} \\ -4 x^2+9 x-2=0 \\\end{array} \\ \\ \text{use either completing the square or quadratic formula and solve for x}\]