Question

Plz help mid life problem here!!!!
Find the standard form of the equation of the parabola with the given characteristic(s) and the vertex at the origin.....??????

Answer 1

y = x^2

Answer 2

How can u plZ explain.?????

Answer 3

If you plot y against x for y = x^2
When x = 0, y = 0
When x = 1, y = 1
When x = 2, y = 4
When x = -1, y = 1
When x = -2, y = 4
Plot these points on a graph, and you will obtain the required parabola.

Answer 4

Wait the directrix is y=3

Answer 5

Sorry

Answer 6

The vertex of a parabola of the form \(y=ax^2+bx+c\) is located at the following point.\[\huge \text{Vertex}=\left(-\frac{b}{2a},\ c-\frac{b^2}{4a}\right)\]So, come up with \(a\), \(b\), and \(c\) that gives a vertex \((0,0)\). (really easy)

Answer 7

I honestly do not understand

Answer 8

Sorr:(

Answer 9

Y

Answer 10

Peas help me!

Answer 11

Please

Answer 12

:(

Answer 13

Plz,!!!!!!!!