Question

solve x^2+6x=10

Answer 1

use completing the square \[\Large x^2 + 6x + (\frac{6}{2})^2 = 10 + (\frac{6}{2})^2\]

Answer 2

that any better?

Answer 3

\[x^2+6x-10=0\]
you can use the quadratic formula
\[x=\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2(a)} \]

Answer 4

\[\begin{array}{l} x^2+6 x=10 \\ \text{Add }9 \text{ to both sides,} \\ x^2+6 x+9=19 \\ \text{Factor the left hand side} \\ (x+3)^2=19 \\ \text{take the square root of both sides} \\ \text{eliminate the absolute value} \\ x+3=-\sqrt{19}\text{ or }x+3=\sqrt{19} \\ \text{subtract }3\text{ from both sides} \\ x=-3-\sqrt{19}\text{ or }x+3=\sqrt{19} \\ \text{Subtract }3\text{ from both sides} \\ x=-3-\sqrt{19}\text{ or }x=-3+\sqrt{19} \\\end{array}\]

Answer 5

i don't get it

Answer 6

The quadratic formula seems easier. Just \(a=1\), \(b=6\), \(c=-10\) then use the fomula..

Answer 7

i do now!!!!!!!

Answer 8

@Mimi_x3 and his formulas :p

Answer 9

"his" ? lol

Answer 10

lol @Mimi_x3

Answer 11

laughing at me that someone assumes that im a guy? :P