Question

A square and a circle both made out of wire enclose an area of 45.35cm^2. Find when the wires are flattened out, which wire is longer and by how much? Round to the nearest hundredths.

Answer 1

use the equation of the circle to find the radius,then multiply the radius by 2. that will be the diameter

Answer 2

\[A=pi R^2 = L^2\]
R radius of circle and L length of a side of squre.\[C=pi 2R = 2\sqrt{pi A} \]
\[4L= 4\sqrt{A}\]

Answer 3

I am a little confused.

Answer 4

4L is the length of square and C is the length of circle, of wires actually.

Answer 5

I mean to find the radius?

Answer 6

A is 45.35cm^2 pi is 3.141592

Answer 7

Can you help me with the rest of this I am so confused?

Answer 8

R is the radius L is the side length\[45.35cm^2 = 3.14 \times R^2\]
\[\sqrt{45.35/3.14}= R\]
now the length of the circle is C\[C= 2\times 3.14\times R\]
\[C=2 \times 3.14 \times \sqrt{45.35/3.14}= 2 \times \sqrt{3.14 \times 45.35}\]
now the square \[45.35= L^2\]
\[L=\sqrt{45.35}\]
length of the square is 4L\[length of the \square = 4L= 4 \sqrt{45.35}\]
and now you compair C and 4L

Answer 9

I see it now, thanks.