ok so im working with imaginary numbers and in this particular equation i have to solve for b. (3+2i)+(2+bi)=5-4i
how you make calcules with imaginary numbers ?
3+2i +2+bi =
just assum the same terms
im sorry i dont understand what you mean
3+2 = ? and from 2i and bi what can you factorizing out ?
ok im failing this class so your going to have to break it down further than that luis
yes i like to learn you calcule it step by step if you like it the same too ?
just treat i as any other constant.. 3+ 2i + 2 + bi = (3+2) + i(2+b) = 5 -4i for a+ ib = x+ iy ..we always have a= x and b=y that is 2 complex no.s are equal if and only if both the real and imaginary parts are equal.. so equate the imaginary parts on both sides and solve for b..
so now you have understood it ?
yes i get it now thank you everyone
ok good luck bye
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