the five letters of the word NEVER are arranged in random order in a straight line how many different orders of the letters are possible?!
5 possibilities for first letters. 4 for second. 3 for third. 2 for fourth. 1 for fifth. It'd be \(5!\), but then comes a great confusion. THERE ARE TWO E's. Easy. You must see the number of ways to arrange two E's and divide them and i.e., 2! \(\Large \color{MidnightBlue}{\Rightarrow {5! \over 2!} }\)
Final answer is 5 * 4 * 3 = 20 * 3 = 60
okay so this question is asking for permutations, i understand that, but i do not understand why i have to divide by 2! when it is just arrangements of 5 letters... if that never had two E's i would just do 5! so why not now? i thought i would only divide by 2! if it was a combination? so confused
Haha, see. If we name them E1 and E2, and for example, we have this: R E1 E2 V R R E2 E1 V R Well, this makes no difference right? If it mattered about the order of E1 and E2, then it'd be 5! only.
thank you! life saver :P
Haha, another user called me a lifesaver on here today
you literally are... if i faily my math exam tomorrow there is no hope, so the more you clear things up for me the more of my life you save ;D
Haha best of luck
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