Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

There is this series: 1 + (1/2)^p + (1/3)^p + ... + (1/n)^p Where p is a real number. - p >1 - p = 1 - p < 1 And my lecturer wants us to proof that the (p<1) series is divergence using comparison test. And he gave us the example of (p>1) Un -> 1 + (1/2)^p + ... + (1/n)^p Vn (convergence) -> 1 + 1/2 + 1/4 + ... + 1/(2^(n-1)) remember, p>1 1=1 (1/2)^p + (1/3)^p < (1/2)^p + (1/2)^p (1/4)^p + ... + (1/7)^p < (1/4)^p + (1/4)^p + (1/4)^p + (1/4)^p and so on and because of Un'1) series is convergence and we must proof that in (p<1) Un>Vn

OpenStudy (anonymous):

|dw:1337800605215:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!