For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions.

Question

phi · Answer

Do you know what the discriminant is?  It must be 0 or positive for pure real roots.

anonymous · Answer

thats all they gave me for the problem

phi · Answer

Here are the gory details http://en.wikipedia.org/wiki/Quadratic_equation#Quadratic_formula

anonymous · Answer

I don't get how to work this out

anonymous · Answer

do you by chance have any advice on how to work it out?

phi · Answer

You match your equation to the form
$$a x^2 +bx+c =0$$
$$ x^2 + 3x + j = 0 $$
so what is a?  b?  c? 

once you know a,b,c, you use them in
$$ b^2 -4ac ≥ 0$$

phi · Answer

For example, in 
$$ x^2 +3x +j=0 $$ a must be 1