Question

square root help!

Answer 1

7/2.

Answer 2

The last one.

Answer 3

actually it is the third one

Answer 4

how

Answer 5

\[\frac{\sqrt{49}}{\sqrt{2}}=\frac{7}{\sqrt{2}}=\frac{7}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{7\sqrt{2}}{2}\]

Answer 6

thanks satellite, can you show me how to do this one pleaseeeee!

Answer 7

@satellite73

Answer 8

@dpaInc

Answer 9

first of all \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{8}=2\sqrt{2}\) so make that replacement first

Answer 10

ok

Answer 11

\[2\sqrt{3}(\sqrt{3}+2)\]
\[=2\times 3+2\sqrt{2}=6+2\sqrt{2}\] for the first product
try
\[\sqrt{2}(2\sqrt{2}-\sqrt{6})\] and tell me what you get

Answer 12

i don't know how to break that down :/

Answer 13

@dpaInc