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Mathematics 7 Online
OpenStudy (anonymous):

please help!! tricky square roots!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@dpaInc

OpenStudy (anonymous):

you only have two type of roots a fourth root and cube root. if you think of it this way let x be the 4th root of 2 and let y be the 3rd root of 2 then the expression can be thought of as 6x - 14y + 5y + 7x can you simplify this and make the necessary choice?

OpenStudy (anonymous):

im not good with breaking down, can you show me how step by step?

OpenStudy (anonymous):

can you combine like terms here? 6x - 14y + 5y + 7x like terms are the ones with the same variables...

OpenStudy (anonymous):

13x and 19y ?

OpenStudy (anonymous):

13x is correct but you should get -9y also so 13x - 9y is the simplified form.. now all you have to do is replace the x and the y with what we substituted them with and you'll have your answer.

OpenStudy (anonymous):

I'm tied between c and d

OpenStudy (anonymous):

can't be any of those.. do you see the 13 and the 9? in our answer and the choices?

OpenStudy (anonymous):

sorry, 13 and the -9 ...

OpenStudy (anonymous):

no but i thought we had to subtract those, thats why i had the 4 in mind

OpenStudy (anonymous):

you cannot combine unlike terms... only like terms you can combine.... 4th root is different from 3rd root.

OpenStudy (anonymous):

then it must be A

OpenStudy (anonymous):

it's B

OpenStudy (anonymous):

why?

OpenStudy (precal):

|dw:1337813191615:dw| just like dplanc stated combine like terms

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