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What is the domain of f(x)=1/(x+1)-4
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Would it be all numbers except 3? @Eyad
Thats right :)
Thanks so much! =)
you 're welcome so much ;)
no, 3 is a valid x value to plug in
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1/(x+1)+4 1/(3+1)+4 1/4+4 17/4 So 1/(x+1)+4 = 17/4 when x = 3
@jim_thompson5910 : its (x+1)-4 , not (x+1)+4
oh right, my bad, but it still means that the domain of \[\Large f(x)=\frac{1}{x+1}-4\] isn't every real number but 3
the denominator is :[ (x+1)-4 ] x-3=0 , x=3 .
since 3 is still a valid input
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are you sure?
I'm thinking that the denominator is just x+1
@swimgirly95 : what is the denominator ?
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