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(7x)^09^79^x=9^2 solve for x
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is that 7x raised to all those exponents?
\[(7x)^09^79^x=9^2 \]?
yes
ah ok then.
Assuming x does not equal 0 what is \[(7x)^0\]?
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idk.
Do you what \[5^0=?\]
know*
yea
what does it equal?
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\[(anything)^0=1 , \text{ where } anything \neq 0 \]
So \[5^0=1\] And \[(7x)^0=1, \text{ assuming } x \neq 0\]
\[(7x)^09^{7}9^x=9^2\] \[1 \cdot 9^7 9^x=9^2\] \[9^7 9^x=9^2\] Do you know what to do now?
:D yess. thanks
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