Determine whether the matrix has an inverse. If an inverse exists, find it.(pic attached)
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OpenStudy (anonymous):
OpenStudy (anonymous):
first check the determinant, if it is not zero, matrix has an inverse
we can find the inverse of a two by two matrix easily
OpenStudy (anonymous):
k then what
OpenStudy (anonymous):
\[A=\left| \begin{array}{cc} a & b \\ c & d \end{array} \right|\]
\[A^{-1}=\frac{1}{ad-bc} \left|\begin{array}{cc} d & -b \\ -c & a\end{array} \right|\]
OpenStudy (anonymous):
you can see why you need the determinant to be non- zero , because you have to divide by it
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OpenStudy (anonymous):
i got [7 18
[-2 5]
OpenStudy (anonymous):
in your case the determinant is one right?
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
\[ad-bc=-5\times 7-(-18)\times 2=-35+36=1\] is what i get
OpenStudy (anonymous):
so we don't have to worry about dividing by anything
you have a mistake in your answer however
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