Determine whether the matrix has an inverse. If an inverse exists, find it.(pic attached)
first check the determinant, if it is not zero, matrix has an inverse we can find the inverse of a two by two matrix easily
k then what
\[A=\left| \begin{array}{cc} a & b \\ c & d \end{array} \right|\] \[A^{-1}=\frac{1}{ad-bc} \left|\begin{array}{cc} d & -b \\ -c & a\end{array} \right|\]
you can see why you need the determinant to be non- zero , because you have to divide by it
i got [7 18 [-2 5]
in your case the determinant is one right?
i think so
\[ad-bc=-5\times 7-(-18)\times 2=-35+36=1\] is what i get
so we don't have to worry about dividing by anything you have a mistake in your answer however
whats the final answer then
last entry should be -5, not 5
\[A^{-1}=\left| \begin{array}{cc} 7 & 18 \\ -2 & -5 \end{array} \right|\]
maybe that was a typo on your part. don't change the sign of \(a\) and \(d\), just switch them
k
thanks
yw
Join our real-time social learning platform and learn together with your friends!