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Mathematics 20 Online
OpenStudy (anonymous):

Determine whether the matrix has an inverse. If an inverse exists, find it.(pic attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

first check the determinant, if it is not zero, matrix has an inverse we can find the inverse of a two by two matrix easily

OpenStudy (anonymous):

k then what

OpenStudy (anonymous):

\[A=\left| \begin{array}{cc} a & b \\ c & d \end{array} \right|\] \[A^{-1}=\frac{1}{ad-bc} \left|\begin{array}{cc} d & -b \\ -c & a\end{array} \right|\]

OpenStudy (anonymous):

you can see why you need the determinant to be non- zero , because you have to divide by it

OpenStudy (anonymous):

i got [7 18 [-2 5]

OpenStudy (anonymous):

in your case the determinant is one right?

OpenStudy (anonymous):

i think so

OpenStudy (anonymous):

\[ad-bc=-5\times 7-(-18)\times 2=-35+36=1\] is what i get

OpenStudy (anonymous):

so we don't have to worry about dividing by anything you have a mistake in your answer however

OpenStudy (anonymous):

whats the final answer then

OpenStudy (anonymous):

last entry should be -5, not 5

OpenStudy (anonymous):

\[A^{-1}=\left| \begin{array}{cc} 7 & 18 \\ -2 & -5 \end{array} \right|\]

OpenStudy (anonymous):

maybe that was a typo on your part. don't change the sign of \(a\) and \(d\), just switch them

OpenStudy (anonymous):

k

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yw

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