Question

[1/(x+2)-(1/2)]/[x] Help! and show steps please

Answer 1

so basically it looks like this

Answer 2

do u need to solve for x?

Answer 3

i need to simplify

Answer 4

ok

Answer 5

\[\frac{\frac{1}{x+2}-\frac{1}{2}}{x}\times \frac{2(x+2)}{2(x+2)}=\frac{2-(x+2)}{x(2)(x+2)}=\frac{-x}{2x(x+2)}=\frac{-1}{2(x+2)}\]

Answer 6

why did you multiply it by 2(x+2)/2(x+2)?

Answer 7

Because I wanted to cancel all the denominators.

Answer 8

And that's what would cancel the denominators in the numerator so I had to multiply the denominator by the same thing.

Answer 9

is that a general rule for cancelling denoimators? the rule being multiply numerator and denominator by the numerator's denominator?

Answer 10

The general rule is multiply numerator and denominator by the common denominator of ALL denominators.

Answer 11

Then all the denominators will cancel.

Answer 12

ok i get it. thanks for your help :)

Answer 13

yw