I don't understand this question, please help: Write an equation of the circle whose diameter AB has endpoints A(-4,2) and B(4,-4).
find the midpoint of the line segment, that will be the center do you know how to find the midpoint?
I think so, use the midpoint formula right?
right, take the average in each coordinate (i.e. add up and divide by 2) in this case you can just about do it in your head
let me know what you get
Okay I will, hang on.
k
I got my H and K value to be (0,-1)
looks good
now we know it is going to look like \[(x-0)^2+(y-(-1))^2=r^2\] or \[x^2+(y+1)^2=r^2\] so we now need \(r\) right?
and since we have the midpoint and also a point on the circle (actually two points) we can use the distance formula to find \(r^2\) you know the distance formula?
yes i know that formula, hang on so i can write this down
k
for the distance i got d to equal 100
seems rather unlikely lets check
you want the distance between the two points \((0,-1)\) and \((4,-4)\) right?
oh, i messed up. the distance should have equaled 65? if I'm finding the distance between (0, -1) and (4, -4)...
yes, actually you do not need the distance, just the square of the distance because you need \(r^2\) not \(r\) but that is not right either we can use the formula, but first we can think
from 0 to 4 is 4 units in the \(x\) direction, and from -1 to -4 is 3 units in the \(y\) direction, and so by pythagoras the square of the distance is \(3^2+4^2=9+16=25\)
here we are just using the old formula for a right triangle \(a^2+b^2=c^2\) which is the basis for the distance formula
if you want to use the distance formula it is \[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] in this case you get \[\sqrt{4-0)^2+(-1+4)^2}=\sqrt{4^2+3^2}=\sqrt{25}=5\]
i am not sure how you arrived at 65, but i hope it is clear what the answer is \[r=5, r^2=25\]
and your "final answer" is therefore \[x^2+(y+1)^2=25\] that is the equation for this circle
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