Question

how many molecules are there in 57.3g of ethane?

Answer 1

given mass / molar mass * (6.022*10^23) will give u the no of molecules

Answer 2

\[57.3gC2H6 \times \frac{6.02 \times 10^{23} moleculesC2H6}{30gC2H6}\]

Answer 3

Chemical formula of ethane = C2H6
no. of mole of ethane
= 57.3 / (12.0x2+1.0x6)
= 57.3/30
= 1.91 mole

no. of molecules required
= no. of mole x Avogadro's Constant
= 1.91 x (6.02x10^23)
= ?