Question

A certain metallic oxide contained 15% of moisture, 15% silica and the rest metallic oxide. after partial drying it contained 5% of moisture what is the % silica in the partially dried sample?

Answer 1

@dpaInc @myininaya @mahmit2012@blues

Answer 2

Hey @shameer1 !
I'm sorry but I don't know any chemistry .

Answer 3

Drying will not eliminate metallic oxide, but it will certainly vaporize the water.

With only 5% water remaining, I would say this is strictly a math problem: keep the silica/metallic oxide ratio the same before and after drying.

Before: 15% water, 15% silica, 70% metallic ore
After: 5% water, x % silica, y % metallic ore

System of equations:
x + y = 95
4.67x = y

I used substitution, and got x ~ 16.8%, so y ~ 78.2%

If anyone else knows better, please post.

Answer 4

initial percentage of moisture=15%
" " " silica =15%
" " " metallic oxide=70%
%ratio of silica to metallic oxide=15/70=3/14
AFTER PARTIAL DRYING
% of moisture = 5%
let percentage of silica be x
percentage of metallic oxide = 95-x
then,
x / 95-x =3/14
=> 14x= 285-3x
=>17x=285
x=16.67% approximately
THE ANSWER IS ~16.67%