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If a side, S, of the base equals 11 ft, then what is the length of the slant height, A, of the pyramid?
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(The right square pyramid below has a surface area of 473 ft2.)
for this you'll need to know how to manipulate with equations. the equation for the Surface are of a square pyramid is Base+(1/2)*4*S*(slant height) 4 because there are four triangles. So then Surface area = S^2 + 2*s*(slant height) s^2 is the base so know, you were give what the surface area was 473=S^2 +2*s*(slant height) now just isolate (slant height) and since you know the value of s (which sorry, sometimes I have capitalized it, but I am referring as s and S as the same thing, side.) just plug in and you'll get what your slant height is.
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