Question

expand (3+x)^5

Answer 1

my answer options are alot bigger than that...

Answer 2

oh right. I forgot. (3+x)(3+x)(3+x)(3+x)(3+x)

Answer 3

243+405x+270x^2+90x^3+15x^4+x^5

Answer 4

that better? :)

Answer 5

thank you! :D

Answer 6

http://www.wolframalpha.com/input/?i=Expand [%283+%2B+x%29^5]
you get
\[x^5+15 x^4+90 x^3+270 x^2+405 x+243
\]

Answer 7

You're welcome :)

Answer 8

\[T= \left(\begin{matrix}n \\ k\end{matrix}\right)*a^{n-k}b^k\]
\((3+x)^5 \)\[=\sum_{r=0}^{5} \left(\begin{matrix}5 \\ r\end{matrix}\right)*(3)^{5-r}*(x)^{r}\]

Answer 9

You have to copy the whole link above and paste in your browser.

Answer 10

even you can use binomial theorem to solve this type of sum !!
(a + b)^n = sum[k=0,n][(n over k)a^(n-k)b^k]
or you can break it in the form of (1+x)^n form
it will be more easier to u