The space shuttle releases a satellite into a circular orbit 650 km above the earth. How fast must the shuttle be moving (relative to earth) when the release occurs.
The answer is 7530 m/s

Question

The space shuttle releases a satellite into a circular orbit 650 km above the earth. How fast must the shuttle be moving (relative to earth) when the release occurs.
The answer is 7530 m/s

anonymous · Answer

for the  satallite to get an orbit?

anonymous · Answer

$$mv^2/(R+h)=GmM/(R+h)^2$$
$$v=\sqrt{MG/(R+h)}$$
M - mass of Earth, value is 6.0 * 10^24 kg
G - gravitational constant, equals to 6.67*10^-11 N m2/kg2
R - radius of Earth, 6.4 *10^6 m
h - given height of satellite.