If a sample of dilute hydrogen peroxide is left standing it will undergo disproportionation.
Discuss the reaction that occurs. Include observations and equations in your discussion and a reason for the reaction that occurs.

Question

If a sample of dilute hydrogen peroxide is left standing it will undergo disproportionation. 
Discuss the reaction that occurs. Include observations and equations in your discussion and a reason for the reaction that occurs.

anonymous · Answer

$$E ^{0}(H _{2}O _{2}/H _{2}O)=+1.77V    \rightarrow  E ^{0}(O _{2}/ H _{2}O _{2})=+0.68V$$

anonymous · Answer

h202 gives positive potenial . so gibbs free energy change is negative,so spontaneous

vincent-lyon.fr · Answer

In the two couples provided, H2O2 is the stronger oxidising agent AND the stronger reducing agent at the same time.

This is why it will spontaneously react on itself in a disproportionation reaction, forming water and oxygen.