Question

is this ratio or do i solve differently?
If XY = 2,980 feet, WY = 1,490 feet, and XZ = 8,940 feet, then what is the distance of VZ?

Answer 1

Angle X is common to both triangles
\[\tan X=\frac{1490}{2980}\]
Also\[\tan X=\frac{VZ}{8940}\]
\[\frac{VZ}{8940}=\frac{1490}{2980}\]
Can you solve from there?

Answer 2

yeahh 4470 final answer

Answer 3

You are so right. Good work :)