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Mathematics 21 Online
OpenStudy (anonymous):

Need some help.

OpenStudy (anonymous):

\[2/3x ^{2}=50\]

OpenStudy (unklerhaukus):

\[\frac{2}{3}x^2=50\qquad\text{or}\qquad \frac{2}{3x^2}=50\]

OpenStudy (anonymous):

The first one.

OpenStudy (unklerhaukus):

multiply both sides by 3 and divide both sides by 2\[\frac{2}{3}x^2=50\]\[\downarrow\]\[x^2=\frac{50\times3}{2}\]

OpenStudy (anonymous):

then to get it just X how do you do that?

OpenStudy (unklerhaukus):

next take the square root of both sides \[x\pm=\sqrt\frac{50\times3}{2}\]

OpenStudy (anonymous):

that is the kind of typo i usually make!

OpenStudy (unklerhaukus):

\[\pm x=\sqrt\frac{50\times3}{2}\]

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

would you break 50 up to 25 and 2?

OpenStudy (unklerhaukus):

you can turn the fraction into a simple number can you rewright it as a product of prime numbers ?

OpenStudy (anonymous):

I have to get it to simplest form... \[x=5\sqrt{2*3\div2}\] would you multiple the 2*3 then divide by 2?

OpenStudy (unklerhaukus):

\[\frac{50\times3}{2}=\frac{25\times2\times3}{2}={5^2\times3}=75\] \[\sqrt{\frac{50\times3}{2}}=5\sqrt{3}\]

OpenStudy (unklerhaukus):

\[x=\pm5\sqrt3\]

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