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Mathematics
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OpenStudy (anonymous):
Need some help.
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OpenStudy (anonymous):
\[2/3x ^{2}=50\]
OpenStudy (unklerhaukus):
\[\frac{2}{3}x^2=50\qquad\text{or}\qquad \frac{2}{3x^2}=50\]
OpenStudy (anonymous):
The first one.
OpenStudy (unklerhaukus):
multiply both sides by 3 and divide both sides by 2\[\frac{2}{3}x^2=50\]\[\downarrow\]\[x^2=\frac{50\times3}{2}\]
OpenStudy (anonymous):
then to get it just X how do you do that?
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OpenStudy (unklerhaukus):
next take the square root of both sides
\[x\pm=\sqrt\frac{50\times3}{2}\]
OpenStudy (anonymous):
that is the kind of typo i usually make!
OpenStudy (unklerhaukus):
\[\pm x=\sqrt\frac{50\times3}{2}\]
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
would you break 50 up to 25 and 2?
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OpenStudy (unklerhaukus):
you can turn the fraction into a simple number
can you rewright it as a product of prime numbers ?
OpenStudy (anonymous):
I have to get it to simplest form... \[x=5\sqrt{2*3\div2}\] would you multiple the 2*3 then divide by 2?
OpenStudy (unklerhaukus):
\[\frac{50\times3}{2}=\frac{25\times2\times3}{2}={5^2\times3}=75\]
\[\sqrt{\frac{50\times3}{2}}=5\sqrt{3}\]
OpenStudy (unklerhaukus):
\[x=\pm5\sqrt3\]
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