Question

describe how you would verify the zeros of the function x3 – 3x2 – 16x + 48?

Answer 1

I would use a calculator to find a zero first

Answer 2

I know what the zero's are, its just that i dont understand what it means by verify

Answer 3

oh just expand your factored term

Answer 4

just listing the factors with the + or -?

Answer 5

Lets say the zeros are
x=3 x=4 x=-4
then
(x-3)(x-4)(x+4)
then expand and verify if you got the same equation
x3 – 3x2 – 16x + 48

Answer 6

\[x^3-3x^2-16x+48=x^2(x-3)-16(x-3)=(x-3)(x^2-16)=(x-3)(x-4)(x+4)=0\]

Answer 7

\[(x-3)(x^2-16)=(x-3)(x-4)(x+4)=0\]

Answer 8

If the product of factors is zero, one of the factors is 0 so:
x-3=0 or x-4=0 or x+4=0
Solving, we have:
x-3, x=4, x=-4
We have just verified the zeros of the function.

Answer 9

Thanks man!

Answer 10

yw