Find the coordinates of the other endpoint when you are given the midpoint and one of the endpoints. Answer in terms of a decimal rounded to the nearest tenth or an improper fraction in simplest form.
P1 M P2
(3, 5) (-2, 0) ( , )
helpppp
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OpenStudy (anonymous):
-2=(x-3)/2
0=(y-5)/2
This?
OpenStudy (anonymous):
please show me step by step :/ idk how to do this
OpenStudy (anonymous):
well midpoint=(xf-xi)/2
OpenStudy (anonymous):
Plug and solve for unknown
OpenStudy (anonymous):
@timo , isn't it supposed to be -2=(x+3)/2 ?
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OpenStudy (anonymous):
hmm
i'll check
OpenStudy (anonymous):
but idk how to solve that -2=(x+3)/2 i need help..
OpenStudy (anonymous):
ah yes it is plus
OpenStudy (anonymous):
midpoint is (averate of the xs, average of the ys)
OpenStudy (anonymous):
just multipy by 2 first and subtract 3
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OpenStudy (anonymous):
so it would b 3?
OpenStudy (anonymous):
i get -7 for x
OpenStudy (anonymous):
how??
OpenStudy (anonymous):
-2=(x+3)/2
multiply by 2 both sides
-4=x+3
subtract by 3 both sides
-7=x
:)
OpenStudy (anonymous):
ohhhhhhhhhhhhhhhhhhhhhhh
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OpenStudy (anonymous):
duh -.- THANKS!
OpenStudy (anonymous):
for Y it is the same way
0=(y+5)/2
0=y+5
-5=y :)
OpenStudy (anonymous):
LOL :) Who are you and what did you do with seashell :P?
OpenStudy (anonymous):
hahhaaha...
OpenStudy (anonymous):
blonde lazy morning -.-
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OpenStudy (anonymous):
but woudnt you multiply the zero by 2?
OpenStudy (anonymous):
Yes and it will make it 0
OpenStudy (anonymous):
Id slap myself
OpenStudy (anonymous):
::P No way I seen you here before :) maybe you do your better work at night :)