Question

solve for x using logarithms(round to 3 decimal places) 5x=100

Answer 1

i am going to assume that this is \(5^x=100\) in which case use the change of base formula
to solve \(b^x=A\) for \(x\) use \(x=\frac{\ln(A)}{\ln(b)}\)

Answer 2

in your case you want
\[x=\frac{\ln(100)}{\ln(5)}\] or you can use
\[x=\frac{\log(100)}{\log(5)}\] and then a calculator

Answer 3

here is what i get, is it right?
x=log5 7=1.209