Question

Hey @satellite73 I have another kind of problem for you. If possiable. 7x^2/√x^5

Answer 1

\[\frac{7x^2}{\sqrt{x^5}}\]?

Answer 2

Yep.

Answer 3

ok denominator is
\[\sqrt{x^5}=x^2\sqrt{x}\]

Answer 4

k so you just used the thing you taught me last night right.

Answer 5

now you can rewrite it as
\[\frac{7x^2}{x^2\sqrt{x}}\]
yup, but we are not done yet

Answer 6

the 2 goes into 5, two times with the remainder of 1.

Answer 7

yes, exactly

Answer 8

k

Answer 9

that is how we go from
\[\sqrt{x^5}\] to
\[x^2\sqrt{x}\]

Answer 10

k.

Answer 11

but there is more to do
you have
\[\frac{7x^2}{x^2\sqrt{x}}\]

Answer 12

you can cancel an \(x^2\) top and bottom to get
\[\frac{7x^2}{x^2\sqrt{x}}=\frac{7}{\sqrt{x}}\]

Answer 13

and finally, if you want to write this in "simplest radical form" i.e. with no radical in the denominator, multiply top and bottom by \(\sqrt{x}\) to get
\[\frac{7}{\sqrt{x}}=\frac{7}{\sqrt{x}}\times \frac{\sqrt{x}}{\sqrt{x}}=\frac{7\sqrt{x}}{x}\]

Answer 14

some people don't like radicals in the denominator, some don't care. either way it is the same

Answer 15

hmmm.

Answer 16

up to your teacher really

Answer 17

for example
\[\frac{1}{\sqrt{2}}=\frac{1}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2}\] just two different forms of the same number

Answer 18

Well the answers have radicals in them. sooo