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Mathematics 24 Online
OpenStudy (anonymous):

Look at the squares, ABCD, CEFG, and PQEB in the figure shown below. Which fact can be best used to prove that BC2 + CE2 = BE2? Answer Area of PQEB is greater than the square of the area of ABCD. Area of PQEB is greater than the square of the area of CEFG. Area of PQEB is equal to the sum of the areas of CEFG and ABCD. Area of CEFG is equal to the sum of the areas of PQEB and ABCD.

OpenStudy (anonymous):

OpenStudy (anonymous):

arent the two sides suposed to add up to more than the hypotenuse not equal?

OpenStudy (anonymous):

I'm pretty sure this uses the transitive property of equality. I'm gonna look at it more though.

OpenStudy (anonymous):

mmks thank-u

OpenStudy (anonymous):

This also uses the pythagorean theorem. Do you have any answers you can rule out because of this?

OpenStudy (anonymous):

the last two if im correct when i say the two other sides should add up to more than that of the hypotenuse?

OpenStudy (anonymous):

Yep! And the hypotenuse is CE.

OpenStudy (anonymous):

ok so i thoght when first going over it that it was the first one but i wasnt sure if i could rule out the last two yet

OpenStudy (anonymous):

So it's : Area of PQEB is equal to the sum of the areas of CEFG and ABCD. right?

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