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Mathematics 23 Online
OpenStudy (anonymous):

use the substitution formula to evaluate the integral 3cos^(2)xsinxdx when x=pi/3 to 2pi i got: -21/8???

OpenStudy (experimentx):

try using integration by parts ... (and substitution for integrating trigonometric part)

OpenStudy (experimentx):

also you can verify the result from wolfram!!

OpenStudy (anonymous):

I did try to use wolfram..but it gave me something different..

OpenStudy (experimentx):

looks like i misinterpreted your integral wolfram is rarely wrong http://www.wolframalpha.com/input/?i=integrate+3cos^2x+sinx+from+pi%2F3+to+2pi

OpenStudy (experimentx):

click show steps to view the ... integral http://www.wolframalpha.com/input/?i=integrate+3cos^2x+sinx

OpenStudy (anonymous):

oh my! how did you get that...? i got like -6.0818 or something..

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