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3q^8/√q^19
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Simplify please
@Mertsj :)
@jim_thompson5910 PLEASE!
I already figured it out. the answer is \[3\sqrt{q} / q\]
but if you could help me with another one?
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Ill get it.
yes it is.
What is it then...
I just simplified.
here is the next one.
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\[\sqrt{24} / 2\sqrt{64}\]
\[\frac{3q^8}{q ^{\frac{19}{2}}}=\frac{3}{q ^{\frac{3}{2}}}=\frac{3\sqrt{q}}{q^2}\]
Hmm thats what i did i thought it was 3√q/q hhm thanks for the correction. and can you do the next one.
\[\frac{2\sqrt{6}}{16}=\frac{\sqrt{6}}{8}\]
Thanks! :D
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yw
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