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How many distinguishable permutations can be made using "SEATTLE". Please explain how to do it because I need to know how to do these.
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just a factorial, but not counting the doubles of the number?
I think so because the problem says distinguishable.
\[\frac{7!}{(2!)(2!) }=210 \]
I understand the 7! part, but why would (n - r)! be 2?
This is a math team question, so they gave me the answers, but not the explanations.
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Btw, the answer is supposed to be 1260. How do I get that?
There are total 8 letters out of which the letters T and E are repeated twice. So the total number of permutations is divided by the permutations of the repeated elements.
7 letters, that is.
Ok.But you got 210. It's supposed to be 1260.
kk
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just a typo. thats all.
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