Question

Solve for x.
lnx(x^2-3x-4)+lnx(x^2-9x+20)=0

Answer 1

@Mertsj please help!

Answer 2

couldnt you factor the x out as well?

Answer 3

whered the e^0 come from?

Answer 4

1?

Answer 5

wait what? sorry i was just guessing about the base i dont know..

Answer 6

after factoring, you could also say this
\[\ln x^{2}(x+1)(x-4)^{2}(x-5) = 0\]

Answer 7

it doesn't matter what the base is....a^0 = 1

Answer 8

I will leave you in the capable hands of dumbcow as too many cooks spoil the broth. Good Luck.

Answer 9

haha

Answer 10

lnx(x^2-3x-4)+lnx(x^2-9x+20)=0 whats next after this?

Answer 11

umm i meant to type what mertjs put but he deleted his answer :/

Answer 12

well basically you have to find the roots of a 6th degree polynomial
\[x^{2}(x-4)^{2}(x+1)(x-5) = 1\]
from analyzing the graph, you know that solution is less than -1 and greater than 5