Question

Solve 4^(x + 7) = 6^(x – 1) can someone solve this please? im having trouble..

Answer 1

do you know how to turn it into logarithmic form?

Answer 2

like into x+7 log4 kinda thing?

Answer 3

\[\Large \log_4 6^{(x-1)} = x+7\]
now you use power rule...

Answer 4

how does the x+7 get isolated?

Answer 5

you use power rule on \(\large \log_4 6^{(x-1)}\) first

Answer 6

power rule?

Answer 7

\[\large \log_a b^x = x log_a b\]

Answer 8

can you just show me the problem so that i will know what im trying to do?

Answer 9

think of \[\large \log_4 6^{(x-1)}\] as \[\large \log_a b^c\]

Answer 10

what is a, b and c?

Answer 11

okay i have that part

Answer 12

so turn it into \[\large c\log_a b\] what do you havE?

Answer 13

x-1log4^6?

Answer 14

hmm close \[(x-1) \log_4 6\] it should be written (x-1)log_4 6 but anyway...solve \(\log_4 6\) in your calculator