How do i determine a formula for the polynomial function whose graph has zeros (x+5) ( x +1) (x-4) and a y intercept of -40
it looks like you have it already. only one step left
i assume you mean the zeros are -5,-1 and 4
i tried f(x) = -40 (x+5).... etc yes those are the zeros
the only thing you don't have is the leading coefficient so write \[p(x)=a(x+5) ( x +1) (x-4) \] then you know \[p(0)=-40\] so write \[a(5\times 1\times -4)=-40\] and solve for \(a\)
a= 2
clear or no? y intercept is what you get when \(x=0\) yes, it is 2
how do i write that out
2x^3 + 5x^2 + x
not sure what you mean. you have it
oh you mean how to you multiply out? you just have to grind it til you find it. do a bunch of multiplications, or else cheat
ohhh ok .. 2(x+5)(x+1)(x-4) then yeah.. from there i guess i need to do the math.. thats no prob though.. thanks a lot
yes, as they say "do the math" i like cheating, that way i know it is right
yes that looks like my graph too.. haha. thank you
yw
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