ok my problem is 6+2(x-7)=10-3(x-3) 6+2x-14=10-3x+9 -8+2x=19-3x -27=-5x and the answer is x=27/5 but what my new problem is that i need to do a check step and i have no clue
Plug in 27/5 for x in the original equation and see if both sides are still equivalent.
i put in 27/5 and got 5.4
Ok, so you got 5.4 which is correct. Now plug that into the original equation and see if both sides are equivalent\[6+2(5.4-7)=10-3(5.4-3)\]
yea i just divide 27 by 5 i am sorry i have no clue what to do iam dumb
i try to do alot on my own but if i fail this class then its 1000 out of my own pocket
Not dumb...just learning. Your problem asked you to solve for x and you found it to be 5.4. If 5.4 is the correct answer then both sides of the equation will come to the same value (ie: they are equivalent) and your answer has been shown to be correct. \[6+2(5.4-7)=2.8\]\[10-3(5.4-3)=2.8\]
Since both answers are 2.8, your answer of 27/5 (or 5.4) is valid.
ok that sounds like i get that some
If you had come up with a different value of x then most likely the above tests would have shown two different answers...telling you that you did something wrong. This is all just a way to check your answer.
ohhh but why is it inportant taht we do that
Well, if you didn't do that how would you know that you performed the algebra correctly?
For simple problems you can probably just double-check your algebra and be fine...but when the problems get a lot harder, it's nice to be able to check your answers. Imagine what could happen if you built a rocket based on unchecked math :P
ok i can understand why when you explan it like that
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