Which represent the first two terms of the sequence: a(little)1 = 2 and a(little)n = -4(a(little)n -1)^2?
a. -16, -1024
b. 64; 65,536
c. 2, -16
d. 2, 64
Please explain!

Question

Which represent the first two terms of the sequence: a(little)1 = 2 and a(little)n = -4(a(little)n -1)^2?
a. -16, -1024
b. 64; 65,536
c. 2, -16
d. 2, 64
Please explain!

anonymous · Answer

$$
a_1=2\ a_n=-4(a_{n-1})^2
$$The question is asking for $a_1,a_2$. You've already been given $a_1$, now find $a_2$ by the formula given for $a_n, n=2$.

anonymous · Answer

@nbouscal  Can you please explain how to find a(little)2?

dumbcow · Answer

$$a_{2} = -4(a_{1})^{2}$$

anonymous · Answer

So you would get -4(2)^2, which equals (-8)^2. So the answer would be d. 2, 64?

dumbcow · Answer

no use order of operations...only the 2 is being squared Not the -4

anonymous · Answer

So, it would be -4(2)^2, so (-4)(4) which is -16, so the answer is c. 2, -16?

dumbcow · Answer

correct

anonymous · Answer

Okay! Thank you! :)