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solve for x: log6(x+5)+log6(3)=log6(24)
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log6(x+5)+log6(3)=log6(24) log6(x+5)+log6(3)-log6(24)=0 using laws of logarithm, \[ log_6\frac{(x+5)(3)}{24}=0\] \[6=\frac{(x+5)(3)}{24}\] can you solve for x now?
trying
yeah i'm stuck... do you distribute the 3?
yes
I end up with 6= 3x+15 all over 24 right?
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right?
x=43?
thanks
Yes
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