Question

find all roots of x^6-13^4+39x^2-27=0

Answer 1

x^6-13^4+39x^2-27=0

^

x there?

Answer 2

factor again if you missing the x there

(x-1)*(x+3)*(x-3)*(x+1)*(x^2-3)

Answer 3

[x = 1], [x = -3], [x = 3], [x = -1], [x = sqrt(3)], [x = -sqrt(3)]

Answer 4

no their is an x right after the 13^4

Answer 5

you missing the x Jean :)

Answer 6

yes I know, it is x^6-13^4x+39x^2-27=0

Answer 7

(x-1)*(x+3)*(x-3)*(x+1)*(x^2-3) =0

Answer 8

So would it be 1,-3,3,-1.

Answer 9

yes and sqrt(3) -sqrt(3)

Answer 10

YOU FORGET
(x^2-3) =0

add 3

x^2=3

take sqrt

x= plus or minute sqrt(3) -sqrt(3) sqrt(3)

Answer 11

plus or minus*

Answer 12

Um so the answer is 1,sqrt(3), sqrt(3),-1, and x=plus or minus 3. I am a little confused.

Answer 13

1,-3,3,-1. are roots

but also -sqrt(3) and sqrt(3)

Answer 14

okayyy. I get it now.

Answer 15

Good job Marge :D