A largest pumped storage power operate allowing water to fall to a lower reservoir through a drop of 500m, passing through six turbines on the way which generate 310 MW of power.
Q.water has a density of 1000kg/m^3, what is the minimum volume of water that must flow through each turbine each second?

Question

A largest pumped storage power operate allowing water to fall to a lower reservoir through a drop of 500m, passing through six turbines on the way which generate 310 MW of power.
Q.water has a density of 1000kg/m^3, what is the minimum volume of water that must flow through each turbine each second?

stormfire1 · Answer

First calculate the mass of water required to generate 310 MJ:
$$3.1x10^8=(9.8m/s^2)(500m)mass$$$$mass=6.327x10^4kg$$Now that you have the mass calculate the volume:$$\frac{6.327x10^4kg}{1000kg/m^3}=6,327m^3$$

anonymous · Answer

We are asked about volume of water flowing through each turbine, so we must divide the last number by 6, cause there are 6 turbines and they all generate this power together.

stormfire1 · Answer

@ArchiePhysics: Good catch...I missed the "each" part in the last sentence.

@bebep207: The final answer above needs to be divided by 6 which leaves you with:
$$1054.5m^3 ~of~water~per~turbine$$

anonymous · Answer

stormfire1, ure the best x). ty archie for the correction