Question

Find g^-1(x) when g(x)=sqrt(x+3)

Answer 1

\[y=\sqrt{x+3}\]

first you interchane the variable x and y

\[x=\sqrt{y+3}\]

solve for y by squaring both sides

\[x^2=y+3\]

subtract 3 from both sides to get

\[x^2-3=y\]

Answer 2

I see! =) So my final answer should be y=x^2-3

Answer 3

yep there is a systematic way of doing this

1)interchange x and y
2)solve for y

Answer 4

Thank you so much!

Answer 5

there is a way to check this also

Answer 6

since we know that the domain of sqrt of x+3 is as semi circle with radius 3 , we can see that they're inverses that are reflected upon the x axis