An Infinite Geometric sequence Such :
\[S \infty =81/2 , Sn/Tn=(3^n-1)/2\]
,Find The G.s ???
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OpenStudy (experimentx):
Sinf??
OpenStudy (anonymous):
Sum to infinity :D
Its rule is
S∞ =a/1-r .
OpenStudy (experimentx):
you should have written more explicitly
OpenStudy (anonymous):
what do u mean ?
OpenStudy (experimentx):
sum up to infinity
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OpenStudy (anonymous):
An infinite geometric series is an infinite series whose successive terms have a common ratio. Such a series converges if and only if the absolute value of the common ratio is less than one ( | r | < 1 ).
OpenStudy (anonymous):
lol ,thats all what I know xD
OpenStudy (anonymous):
I think its we can apply the rule only ..
OpenStudy (experimentx):
put n=2 ...
OpenStudy (experimentx):
1/r + 1 = 8
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OpenStudy (experimentx):
find the value of a from the left relation
OpenStudy (anonymous):
u mean 1-r ,but why u put a =1 ?
OpenStudy (experimentx):
Oh ... sorry ... forgot to divide by 2
OpenStudy (experimentx):
ignore that post ... i wasn't thinking
OpenStudy (anonymous):
nvm :)
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OpenStudy (anonymous):
sry for asking many questions :/
OpenStudy (experimentx):
\[ \frac{S_2}{T_2} = 4 = \frac{a +ar}{ar}\]
find the value of r from here
get the value of a from other relation
OpenStudy (anonymous):
aha...
OpenStudy (anonymous):
@satellite73 : can u help :)
OpenStudy (anonymous):
@experimentX :from where u got that 4 in Sn/Tn=4=... ?
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OpenStudy (experimentx):
from your second relation ... put n=2
OpenStudy (anonymous):
oh, OK
OpenStudy (experimentx):
you will get the value of r from here
use your first relation to get the second value