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that isnt a question!
do you want us to solve \[a^2 - 5a - 20 = 0\] ?
do u have to factor it
yeah
i gave it how its given to me
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\[\huge a^2-5a-20=0\] \[\huge a=\frac{5-\sqrt{25-4(-20)}}{2} = \frac{1}{2}(5-\sqrt{105})\] \[\huge a=\frac{5+\sqrt{25-4(-20)}}{2} = \frac{1}{2}(5+\sqrt{105})\]
What is the question
It is a parabola with 2 roots
ok so u would do the quadratic formula , so it would be x=5plus or minus isqrt of 55 over 2
nvm i got thank you cyter and thanks for all your hellp everyone else.
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got it*
ur welcome
ur welcome
ur welcome
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