Question

Please help me with the problem below.

Thanks

Answer 1

look at the numerator it needs a common denominator

\[\frac{x(x+4) +6(x -4)}{(x -4)(x+4)}\]

factorise the denominator

\[\frac{3}{2(x^2 - 16)} = \frac{3}{2(x-4)(x+4)}\]

when dividing by a fraction invert and multiply

the problem is now

\[\frac{x(x+4) + 6(x-4)}{(x -4)(x+4)} \times \frac{2(x -4)(x+4)}{3}\]

the common factors can be removed (x-4)(x+4) and then just collect like terms to finish the simplification.

Answer 2

Thanks very much. No one else helped me but thank you and good job.

Answer 3

hope you got

\[\frac{2(x^2 + 10x - 24)}{3}\]

Answer 4

Yes thank you.