While a person is walking, his arms swing through approximately a 45.0 angle in 0.510 . As a reasonable approximation, we can assume that the arm moves with constant speed during each swing. A typical arm is 70.0 long, measured from the shoulder joint. What is the acceleration of a 2.00 gram drop of blood in the fingertips at the bottom of the swing? Please help!!!

Question

While a person is walking, his arms swing through approximately a 45.0 angle in 0.510 . As a reasonable approximation, we can assume that the arm moves with constant speed during each swing. A typical arm is 70.0  long, measured from the shoulder joint.  What is the acceleration of a 2.00 gram drop of blood in the fingertips at the bottom of the swing? Please help!!!

anonymous · Answer

0.510  um what is this for?

anonymous · Answer

that is the time. The arm swing the angle  in 0.510 seconds...

anonymous · Answer

frm an equilibrium position?

anonymous · Answer

while he is walking..he is swinging his arm..that was the teacher explanation :/

anonymous · Answer

I got it tinman thank you anyways

anonymous · Answer

ok no problem can u tell me how plz!

anonymous · Answer

sure: acceleration is equal to v^2/radius,..the radius is given (.7m since that is how long the arm is. changed from 70 cm to meters btw). the velocity you find it like this v=2pi *.7/4(time). Then just plug the number in the first equation

anonymous · Answer

uh thanks for the medal :)

anonymous · Answer

no problem