Plz solve:)

Question

Plz solve:)

maheshmeghwal9 · Answer

$$\sin^{-1} \sin (10^c)$$
Where 'c'=radians.

maheshmeghwal9 · Answer

Solution attached:- Here in solution $$p=\pi.$$

maheshmeghwal9 · Answer

attachment

maheshmeghwal9 · Answer

Plz help me make understand the solution or u give another method of solving:)

anonymous · Answer

inverse sine only gives back a number between -pi/2 and pi/2.  but the domain of inverse sine is restricted to -1 to 1.

maheshmeghwal9 · Answer

I didn't understand & I want only this much that why he took 3pi-10

maheshmeghwal9 · Answer

@dpaInc

maheshmeghwal9 · Answer

@kropot72 Please help:)

anonymous · Answer

I'm not sure if this helps, but I plugged your info in and got this http://www.wolframalpha.com/input/?i=sin%5E%E2%88%921sin%2810%5Ec%29

maheshmeghwal9 · Answer

Plz help:)

kropot72 · Answer

It appears that the solver used some type of transformation to bring 10 radians into the domain of the inverse sine. 
In the transformation $$p=\frac{20}{3}radians$$

maheshmeghwal9 · Answer

but how p=(20/3)^c

apoorvk · Answer

so 10 radians = 570 degrees right?

then in which quadrant does '570 degrees' appear?

maheshmeghwal9 · Answer

@.Sam. Please help:)

anonymous · Answer

I think it's $3\pi -10^c $

maheshmeghwal9 · Answer

all are trying to do question but I am not getting what is happening in the question:(

maheshmeghwal9 · Answer

this is not a mountain question, which can't be broken. So, please help in a better way:)

maheshmeghwal9 · Answer

Thanx! to all I have got my question:):):):):)