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Chemistry 16 Online
OpenStudy (anonymous):

The hydrated chloride of a divalent Metal loses 14.73% (by weight) of its mass by dehydration .If one mole of the hydrated salt contain 2 moles of water of hydration calculate the weight % of chlorine in the hydrated salt?

OpenStudy (anonymous):

:/ Sorry.

OpenStudy (apoorvk):

so if the metal chloride is divalent, (let the metal be 'M') - what would the chemical formula of the compound be?

OpenStudy (apoorvk):

@open_study1 - yeah so whaddya think now?

OpenStudy (apoorvk):

Hmm hmm? any idea?

OpenStudy (anonymous):

i founded the Molar mass then what should i do??? @heena plzz help

OpenStudy (callisto):

molar mass of ...?

OpenStudy (anonymous):

ok let the divalent chloride be XCl2 now they said 14.3% is loss by weight now if one mole of salt contain 2mole water and u knw evry mole of water it is 18 means 2mole 2x18=36 so we came to know by total mass u have to just reduce 36 and thats all given in qn now think by the above info wat u can do?

OpenStudy (anonymous):

I got Molar Mass = 137.4

OpenStudy (anonymous):

then

OpenStudy (anonymous):

after subtracting the amount of water u got 137.4 :?

OpenStudy (anonymous):

say?

OpenStudy (anonymous):

@open_study1 u have provided the compound name too otherwise hoe can u get molar mass u can only get amount of percent :O

OpenStudy (anonymous):

sorry thats not molar mass it is the weight of metal 137.4

OpenStudy (anonymous):

@heena sorry!!

OpenStudy (anonymous):

ok u knw 137.4 means metal name is barium now qn is easy see the salt is BaCl2

OpenStudy (anonymous):

ok then wat to do....

OpenStudy (anonymous):

ok nw u kne molecualr wight of bacl2 let percent be 100% from which 14.73% is removed means how much remain?

OpenStudy (anonymous):

85.27

OpenStudy (anonymous):

ok thanzz i got it...... 29%

OpenStudy (anonymous):

ok den :)

OpenStudy (anonymous):

@heena thanxx for helping

OpenStudy (anonymous):

@open_study1 may i ask u one qn whenever i came online i instantly get a call by u i mean do u wait for me to come ?? lol :D :D everytime as i came online i get a call :P :P anyways i love to help u as u really need it as other only post their home work qn -_-

OpenStudy (apoorvk):

Lol why are we making this so complicated? Okay now what we do is- (we don't even need the name of the metal) \[\text{You know that the metal is something of the form } MCl_2\] Now, every mole of the hydrated salt has two moles of H2O in it.\[\text{So, the molecular formula of the hydrated form = }MCl_2.2H_2O\] Now when you are dehydrating one mole of the salt, you are making it lose 2 moles of water, or 36 grams of water. Now, is the weight of of one mole of the salt 9hydrated) is 'x' grams, this '36 grams' is the 14.73% of the weight that each mole uses. so, 14.73% of 'x' = 36 Calculate 'x'. Now this salt contains 2 moles of the Cl atom per mole of itself. That is, 35.5 x 2 = 71 gms per mole. so find out then what percentage of 'x' is 71 grams. That 'll get you the mass percentage of Cl in the salt (hydrated).

OpenStudy (apoorvk):

Oh lol, you folks are done it seems. never mind.

OpenStudy (anonymous):

v.good itna time lete ho qn solve krne m :O u knw its dangeours to take much time..

OpenStudy (anonymous):

anyways i didnt solve this qn i m only giving hint to him, dat how can we move furhter as the main thing is dat which happen wid me too i dont get how to move sometimes :P

OpenStudy (apoorvk):

Lol, it takes time to form it out systematically. otherwise jab main khud karta hoon toh dhada-dhad ye lagaya woh kiya and lo! the answer ;)

OpenStudy (anonymous):

xactly in my cohcing mere teacher jb bhi koi wn dete h and wen he see my notebook not in allen duri coching m pehle y hi sochte h kam kaha kiya h :P

OpenStudy (apoorvk):

haha lol.

OpenStudy (anonymous):

ni sach m :P meri dusri coching k teacher pta h har step likhte h or m shortcut marti rhti hu wek line m hi sara kata piti :P :P

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