50 ML of 0.001 M phosphoric acid are exactly neutralized by the addition of 0.005 N Naoh the molarity of resulting salt is?
i think we have to find milli eq
H3po4 +3Naoh gives na3po4 + 3h20
here is the equation now plzz help me....
ok now calculate moles of each reactants from concentration and then put their moles in ratio relationship from which you can calculate moles of product salt and its molarity
hm..........hm............ @Kryten u changed a lot during these days earlier u was not like this u used to help me(shameer1) by attaching a file i was in a dream that why people like u take that much risk to help me but now i dont know wat is keeping this away from u................any how thanzzz a billion for helping me(shameer1) a lot earlier but at the same time i am also sad that now u are nt.................. drops !!!!
@Kryten i really miss ur help!!
@Kryten u last helped me when ur landlord came to buy rent........
i dont know what you expect from me, you are not the only one who needs help and i am not here to serve you when ever you get homework... if you want like that lets make a deal, you write me a paper on TiZr ceramics and i will solve your homework
and also i wrote you what steps you must do but you dont even want to try to put it all on paper!!!
@Kryten i dont want u to only help me i want u to help me thats only i need
it will be better if u show that....
since i have to do a lot of problems in maths chem physics
of course it will be easier but you wont learn anything and this is as much as i know "open STUDY"!!! not "open SOLVE MY HOMEWORK"!!!
if u write the steps i will come to understand the methods and will ask u if i have doubts these all question are mcq i need to write only the answer for it i already have answers to that ........ i can here to understand the steps.....for doing it..
i told you steps! read what i wrote and do so on paper!
ok after calculating the moles.....next step i didnt understand
c= n/V n= cV -> H3PO4 n(H3PO4):n(NaOH)=???? n(NaOH) = ???? * n(H3PO4) V=n/c ->NaOH n(Na3PO4) = ??? n(H3PO4)....
and thats all from me, im going out...