Determine the perimeter of quadrilateral KLMN with vertices K(-4, 2), L(2, 2), M(8, -3), and N(-10, -6).

6 years agoi dont think theres any shortcut here..you'll have to use distance formulla here.. 4 times here it is,,distance between (x1,y1) and (x2,y2) is sqrt[(x2-x1)^2 + (y2-y1)^2] hope this helps..

6 years agoI did.. but I am getting...48.1

6 years agocan you show your work and we might be able to see where, or if, its got an error in it

6 years agoKL=6, LM=7.8, MN=18.2, NK=16.12

6 years agoL(2, 2), M(8, -3) -2-2 -2-2 --------------- 0,0 6,-5; sqrt(36+25) sqrt(61) , good-ish

6 years agohow accurate does the solution have to be?

6 years agoround it

6 years agoit doesnt have to be too acruarate

6 years agoM(8, -3), N(-10, -6) 10 6 10 6 ------------------- 18, 3 0,0 sqrt(324+9) sqrt(333) = 18.248 , that one checks out too

6 years agoN = -10,-6 -K = 4, -2 ------------ -6,-8; sqrt(36+64) sqrt(100) = 10 , that one looks off

6 years agosubtract 6.12 from your answer and youll should be closer

6 years agoanswer is 42

6 years agoyep, 48.1 - 6.1 = 42

6 years agoTHANK U

6 years agoyoure welcome

6 years ago